10[4-(3-x)]+2x=3(4x+4)-2

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Solution for 10[4-(3-x)]+2x=3(4x+4)-2 equation: 


Simplifying
10[4 + -1(3 + -1x)] + 2x = 3(4x + 4) + -2
10[4 + (3 * -1 + -1x * -1)] + 2x = 3(4x + 4) + -2
10[4 + (-3 + 1x)] + 2x = 3(4x + 4) + -2

Combine like terms: 4 + -3 = 1
10[1 + 1x] + 2x = 3(4x + 4) + -2
[1 * 10 + 1x * 10] + 2x = 3(4x + 4) + -2
[10 + 10x] + 2x = 3(4x + 4) + -2

Combine like terms: 10x + 2x = 12x
10 + 12x = 3(4x + 4) + -2

Reorder the terms:
10 + 12x = 3(4 + 4x) + -2
10 + 12x = (4 * 3 + 4x * 3) + -2
10 + 12x = (12 + 12x) + -2

Reorder the terms:
10 + 12x = 12 + -2 + 12x

Combine like terms: 12 + -2 = 10
10 + 12x = 10 + 12x

Add '-10' to each side of the equation.
10 + -10 + 12x = 10 + -10 + 12x

Combine like terms: 10 + -10 = 0
0 + 12x = 10 + -10 + 12x
12x = 10 + -10 + 12x

Combine like terms: 10 + -10 = 0
12x = 0 + 12x
12x = 12x

Add '-12x' to each side of the equation.
12x + -12x = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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